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# If A and B are matrices of same order ,then (AB'-BA') is a

$\begin{array}{1 1}(A)\quad skew\;symmetric & (B)\quad null\;matrix\\(C)\quad symmetric\;matrix & (D)\quad unit\;matrix.\end{array}$

Answer is (A) skew symmetric matrix,because (A$B'$-B$A'$)=(A$B')'-(BA')'$
$(B')'A'-(A')'B'\Rightarrow BA'-AB'$
$\Rightarrow (-)(AB'-BA')$