logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Match the each of the diatomic molecule in column-I with the bond orders are given in the column -II

 

$\begin{array}{1 1}(1) (a ) \rightarrow (r), (b) \rightarrow (q) , (c ) \rightarrow (p) , (d) \rightarrow (s)\\(2) (a ) \rightarrow (r), (b) \rightarrow (p) , (c ) \rightarrow (s) , (d) \rightarrow (q)\\(3) (a ) \rightarrow (r), (b) \rightarrow (s) , (c ) \rightarrow (p) , (d) \rightarrow (q)\\(4) (a ) \rightarrow (r), (b) \rightarrow (s) , (c ) \rightarrow (q) , (d) \rightarrow (p)\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
The bond order of $N_2, O_2, O_2^+$ and $O_2^-$ are 3, 2,2.5 and 1.5 respectively
Hence (3) is the correct answer.
answered Dec 9, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...