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# Match the each of the diatomic molecule in column-I with the bond orders are given in the column -II

$\begin{array}{1 1}(1) (a ) \rightarrow (r), (b) \rightarrow (q) , (c ) \rightarrow (p) , (d) \rightarrow (s)\\(2) (a ) \rightarrow (r), (b) \rightarrow (p) , (c ) \rightarrow (s) , (d) \rightarrow (q)\\(3) (a ) \rightarrow (r), (b) \rightarrow (s) , (c ) \rightarrow (p) , (d) \rightarrow (q)\\(4) (a ) \rightarrow (r), (b) \rightarrow (s) , (c ) \rightarrow (q) , (d) \rightarrow (p)\end{array}$

The bond order of $N_2, O_2, O_2^+$ and $O_2^-$ are 3, 2,2.5 and 1.5 respectively
Hence (3) is the correct answer.