Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The correct order of bond angles of $CH_4, NH_3$ and $H_2O$ are

$\begin{array}{1 1}(a)\;CH_4 < NH_3 < H_2O&(b)\;CH_4 < H_2O < NH_3\\(c)\;CH_4 > NH_3 > H_2O&(d)\;CH_4 > NH_3 = H_2O\end{array}$

Can you answer this question?

1 Answer

0 votes
$ CH_4 > NH_3 > H_2O$
$CH_4(109.50), NH_3(107.50), H_2O(105.50) $
According to VSEPR theory, more the number of lone pairs on a central atom , the greater is the contraction caused in the angle between the bondpairs.
answered Dec 9, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App