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According to VSEPR theory, the number of lone pairs in $PCl_5, IF_5, SOF_4$, and $XeOF_4$

$\begin{array}{1 1}(a)\; 0,0,1\; and \;1&(b)\; 1,0,1\; and\; 0\\(c)\; 0,1,0\; and \;1&(d)\; 1,1,0\; and\; 0\end{array}$

1 Answer

0,1,0 and 1
the number of lone pairs in $PCl_5$ = 0
$ IF_5$ = 1
$SOF_4 $ = 0
$XeOF_4$ = 0
Hence (c) is the correct answer.
answered Dec 9, 2013 by sreemathi.v
edited Nov 22 by sharmaaparna1
 

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