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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The frequency of oscillation in rad/sec of a simple pendulum of length l suspended inside a rocket moving vertically with an acceleration 'a' just above the earth is:

$\begin{array}{1 1}(a)\;0 \\(b)\;\sqrt {\frac{(a+g)}{I}} \\( c)\;\sqrt {\frac{(g-a)}{I}} \\(d)\; \sqrt {\frac{(a-g)}{I}} \end{array}$

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1 Answer

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The net accleration felt by mass m of the pendulum is $a+g$ .
Hence b is the correct answer.
answered Dec 10, 2013 by meena.p
 

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