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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The phase constant, in rad/sec, of a simple pendulum - whose amplitude of oscillation is 'a' initial displacement is 'x', initial velocity is 'v', frequency in rad/sec is 'w' - is equal to:

\begin{array}{1 1}(a)\;\frac{x}{a} \\(b)\;(\frac{x}{a}-\frac{v}{m}) \\( c)\; (\frac{x}{a}+\frac{v}{w}) \\(d)\; \frac{(x * v)}{(a * w)} \end{array}

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1 Answer

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The initial displacement results in phase constant of $\large\frac{X}{a}$ and initial velocity in the direction of displacement reduces it by $\large\frac{v}{w}$
Hence b is the correct answer
answered Dec 10, 2013 by meena.p
 

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