$\begin{array}{1 1}(a)\;6,3.5,3,2 \\(b)\;5,4,1,1 \\( c)\; 7,3,2,1 \\(d)\; All\;of\;the\;above \end{array}$

Let $x =\alpha+ A \sin w t$ be the equation of SHM.

Then $velocity = Aw \cos wt$ & $ acceleration =-Aw^2 \sin wt$ calculate $A \sin wt$ using current position & initial position.

Using equation for acceleration you can find $w^2$.

It will turn out to be negative for all the three cases which makes w to be imaginary which is not possible in an SHM.

Thus 'd' is right.

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