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The phase constant in rad/sec of a simple pendulum whose amplitude of oscillation is 'b', initial displacement is 'y', initial velocity is 'v', frequency in rad/sec is 'w' is

$\begin{array}{1 1}(a)\;\frac{y}{b}\\(b)\;(\frac{y}{b}-\frac{v}{w}) \\( c)\;(\frac{y}{b}+\frac{v}{w}) \\(d)\;\frac{(y*v)}{(b*w)} \end{array}$

1 Answer

The initial displacement results in phase constant of $\large\frac{y}{b}$ and initial velocity in the direction of displacement reduces it by $\large\frac{v}{w}$
Hence b is the correct answer
answered Dec 11, 2013 by meena.p

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