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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The phase constant in radians of a simple pendulum having an initial displacement of 24 units and having an amplitude of .24 is

$\begin{array}{1 1}(a)\;0.375 \\(b)\;0.75 \\( c)\; 1 \\(d)\;This\;motion\;is\;not\;possible \end{array}$
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we can not displace by 24 units with its pivot and get an amplitude of 0.24.
Hence d is the correct answer.
answered Dec 11, 2013 by meena.p

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