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Calculate the solubility product of $AgBr$ in water at $25^{\large\circ}$ from the cell: $Ag,Ag^+Br^-$(Saturated solution). The standard potentials are $E^{\large\circ}_{AgBr,Ag}=0.07V$, $E^{\large\circ}_{Ag^+,Ag}=0.80V$. The $K_{SP}$ Value is

$\begin{array}{1 1}(A)\;4.81\times 10^{-9}&(B)\;4.81\times 10^{-11}\\(C)\;3.42\times 10^{-11}&(D)\;4.1\times 10^{-10}\end{array}$

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