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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Redox Reactions
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The correct representation of $\lambda^{\large\circ}CH_3COOH$ interms of $\lambda^{\large\circ}_{CH_3COOK},\lambda^{\large\circ}_KCl$ is

$\begin{array}{1 1}(A)\;\lambda^{\large\circ}_{CH_3COOH}=\lambda^{\large\circ}_{CH_3COOK}+\lambda^{\large\circ}_{HCl}-\lambda^{\large\circ}_{KCl}\\(B)\;\lambda^{\large\circ}_{CH_3COOH}=-\lambda^{\large\circ}_{CH_3COOK}-\lambda^{\large\circ}_{HCl}+\lambda^{\large\circ}_{KCl}\\(C)\;\lambda^{\large\circ}_{CH_3COOH}=\lambda^{\large\circ}_{CH_3COOK}-\lambda^{\large\circ}_{HCl}-\lambda^{\large\circ}_{KCl}\\(D)\;\lambda^{\large\circ}_{CH_3COOH}=\lambda^{\large\circ}_{CH_3COOK}+\lambda^{\large\circ}_{HCl}+\lambda^{\large\circ}_{KCl}\end{array}$

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1 Answer

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According to Kohlrausch's law,
$\lambda^{\large\circ}_{CH_3COOH}=\lambda^{\large\circ}_{CH_3COOK}+\lambda^{\large\circ}_{HCl}-\lambda^{\large\circ}_{KCl}$
Hence (A) is the correct answer.
answered Dec 10, 2013 by sreemathi.v
 

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