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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Redox Reactions
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$E^o_{Zn^{+2}/Zn}=0.76V,E^o_{Cu^{+2}/Cu}=0.34V$ find $\Delta G^orx_n$ of following cell $Zn/Zn^{+2}\parallel Cu^{+2}/Cu$

$\begin{array}{1 1}(a)\;200KJ\\(b)\;106.15KJ\\(c)\;212.3KJ\\(d)\;424.6KJ\end{array}$

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1 Answer

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Cell $rx_n$ will be
$Zn+Cu^{+2}\rightleftharpoons Zn^{+2}+Cu$
$E^o_{cell}=-E^oZn^{+2}/zn+E^o_{Cu^{+2}/Cu}$
$\Rightarrow 0.76+0.34$
$\Rightarrow 1.1V$
$\Delta G^o=-nFE^0_{cell}$
$n=2$
$\Delta G^o=-2\times 96500\times 1.1J$
$\qquad=212.3KJ$
Hence (c) is the correct answer.
answered Dec 10, 2013 by sreemathi.v
 

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