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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Redox Reactions
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For hydrogen concentration cell in working condition ,the correct relation is

$\begin{array}{1 1}(a)\;P^H anode > P^H cathode\\(b)\;P^H cathode > P^H anode\\(c)\;P^H cathode = P^H anode\\(d)\;None\end{array}$

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1 Answer

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Hydrogen concentration cell
$P^H/H_2/H^P\parallel H^P/H_2/P^t$
$P^H/H_2/H^P\Rightarrow P^H\;anode$
$H^P/H_2/P^t\Rightarrow P^H\;cathode$
$(E_{P-P})anode=-0.059\times P^H anode$
$(E_{P-P})cathode=-0.059\times P^H cathode$
$E_{cell}=0.059(P^Ha-P^Hc)$
$\Delta G_{cell}=-\eta FE_{cell}$
$\quad\quad\;\;=-\eta F\times 0.059$
For working condition $\Delta G_{cell}< 0$
So $P^H_a-P^Hc > 0$
$P^Ha > P^H c$
Hence (a) is the correct answer.
answered Dec 11, 2013 by sreemathi.v
 

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