Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Redox Reactions
0 votes

$E_{AgI/Ag/I^-}=$?,$E^o_{Ag^+/Ag}=0.8V,K_{spAg I}=10^{-18}$

$\begin{array}{1 1}(a)\;0.8V&(b)\;-0.28V\\(c)\;0.4V&(d)\;-0.56\end{array}$

Can you answer this question?

1 Answer

0 votes
By Nernst equation for metal-metal ppt electrode
$E_{Ag^+/Ag}=E^o_{ag^+/Ag}+\large\frac{0.06}{\eta}$$\log K_{sp}$
$\qquad\;\;\;=0.8+\large\frac{0.06}{1}$$\log 10^{-18}$
Hence (b) is the correct answer.
answered Dec 11, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App