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$Cu5O_4$ solution is not stable in $Zn$ container because of

$\begin{array}{1 1}(a)\;\text{because of formation of}(Cu)_25O_4\\(b)\;\text{because of formation of Cu}\\(c)\;\text{because of formation Cu-Zn alloy}\\(d)\;\text{because of formation of }Zn5O_3\end{array}$

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1 Answer

$E^o_{Cu^{+2}/Cu} > E^o_{Zn^{+2}/Zn}$
$Zn(s) +Cu^{+2}(aq)\rightarrow Zn^{+2}(aq)+Cu$
Hence (b) is the correct answer.
answered Dec 11, 2013 by sreemathi.v
 

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