# The resistance of 0.01M of solution of an electrolyte was found to be $150\omega$ at $25^oC$.Calculate equivalent conductance.cell constant =$0.80cm^{-1}$ [For given solution $\eta$ factor =2]

$\begin{array}{1 1}(a)\;265\\(b)\;278\\(c)\;285\\(d)\;255\end{array}$

$R=150 \Omega$
$G=\big(\large\frac{1}{150}\big)\Omega ^{-1}$
Cell constant =$0.80cm^{-1}$
K=cell constant $\times$ conductance
$\;\;=0.80\times \large\frac{1}{150}$
$\;\;=5.33\times 10^{-3}\Omega^{-1}cm^{-1}$
Conc.of $C=0.01mol dm^{-3}$
$\lambda_m=\large\frac{K}{C}$