# $$sin \bigg (\frac{\pi}{3} - sin^{-1} (\frac{1}{2}) \bigg)$$ is equal to $\begin{array} ((A) \: \frac{1}{2} \quad & (B)\: \frac{1}{3} \\ (C)\: \frac{1}{4} \quad & (D) \: 1 \end{array}$

Ans: A

$Sin(\frac{\pi}{3}-\frac{\pi}{6})=Sin\frac{\pi}{6}=\frac{1}{2}$