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Which of following graph is correct?

d) None



1 Answer

For $KCl,NaCl,LiCl$ anionic part is same.$Li^+$(aq) has smallest size means high charge density .So it has high hydration and hence low ionic mobility .So it has low molar conductance .
So $\Lambda_m^{\infty}KCl > \Lambda_m^{\infty}NaCl > \Lambda_m^{\infty}LiCl$
Hence (a) is the correct answer.
answered Dec 12, 2013 by sreemathi.v

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