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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Redox Reactions
0 votes

Which of following is correct statement?

Electrolytic decomposition of NaCl in liquid state in formation of Na at cathode and anode

Electrolytic decomposition of NaCl in formation of Na at cathode and $Cl_2$at anode

Electrolysis of $AgNO_3(aq)$ results in Ag deposited at cathode

Electrolysis of conc.NaCl results in $O_2$ at anode and $H_2$at cathode

Can you answer this question?
 
 

1 Answer

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(a) For liquid NaCl
$NaCl(l)\rightarrow Na^++Cl^-$
$Na^+$-cathode
$Cl^-$-anode
So at anode $Cl^-\rightarrow \large\frac{1}{2}$$Cl_2+e^-$
At cathode $Na^++e^-\rightarrow Na$
(b) For aqueous NaCl
$NaCl(aq)\rightarrow Na^+(aq)+Cl^-(aq)$
At cathode :$2H_2O+2e^-\rightarrow H_2+2OH^-$
At anode :$Cl^-\rightarrow \large\frac{1}{2}$$Cl_2+e^-$(at high concentration)
(c) Anode :$H_2O\rightarrow \large\frac{1}{2}$$O_2+2H^++2e^-$
Cathode: $Ag^++e^-\rightarrow Ag$
(d) For concentrated solution
At cathode : $2H_2O+2e^-\rightarrow H_2+2OH^-$
At anode : $Cl^-\rightarrow \large\frac{1}{2}$$Cl_2+e^-$
Hence (c) is the correct answer.
answered Dec 12, 2013 by sreemathi.v
 

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