Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

For the reaction $aA+bB\rightarrow cC+dD$ the rate of formation of [C] in term of [A] is given by

$\begin{array}{1 1}(a)\;\large\frac{d[C]}{dt}=\frac{c}{a}\frac{d[A]}{dt}&(b)\;\large\frac{d[C]}{dt}=-\frac{a}{c}\frac{d[A]}{dt}\\(c)\;\large\frac{d[C]}{dt}=-\frac{d[A]}{dt}&(d)\;\large\frac{d[C]}{dt}=-\frac{c}{a}\frac{d[A]}{dt}\end{array}$

Can you answer this question?

1 Answer

0 votes
Answer: $-\large\frac{c}{a}\frac{d[A]}{dt}$
In general for the reaction: $aA+bB\rightarrow cC+dD$,
$\quad \large - \frac{1}{a} $$ \large\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=\frac{1}{c}\frac{d[C]}{dt}=\frac{1}{d}\frac{d[D]}{dt}$
$\Rightarrow \large\frac{d[C]}{dt}=-\frac{c}{a}\frac{d[A]}{dt}$
answered Dec 12, 2013 by sreemathi.v
edited Jul 24, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App