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JEEMAIN and NEET
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Chemistry
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Chemical Kinetics
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In an experiment (reactant $\rightarrow$ product) we observe that if we increase the reactant to twice then time taken in the concentration of reaction to drop to $\large\frac{1}{2}$ of its value is reduced to $\large\frac{1}{4}$ then order is
$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;3$
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