$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;3$

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$t_{\large\frac{1}{2}}\propto [A]^{1-n}$

$t_{\large\frac{1}{2}}=P [A]^{1-n}$

A = Rate of concentration of the reaction

t = Time taken

P=constant of proportionality

$\large\frac{1}{4}$$t_{\large\frac{1}{2}}=P[2A]^{1-n}$

$4=[\large\frac{1}{2}]^{1-n}$

$4=[2]^{n-1}$

$2^2=[2]^{n-1}$

$n=3$

Hence (d) is the correct answer.

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