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Gaseous phase decomposition of $N_2O$ is given below :

Step 1:$N_2O(s)\rightarrow N_2(g)+O(g)$

Step 2:$O(g)+N_2O(g)\rightarrow N_2(g)+O_2(g)$

then $Rx^n$ intermediate is

$\begin{array}{1 1}(a)\;N_2O(g)&(b)\;N_2(g)\\(c)\;2N_2O(g)&(d)\;O(g)\end{array}$

Can you answer this question?

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Answer: O(g)
$2N_2O(g)\rightarrow 2N_2(g)+O_2(g)$
The O atom is an intermediate because it is formed and then consumed during the course of the reaction.
answered Dec 13, 2013 by sreemathi.v
edited Jul 25, 2014 by balaji.thirumalai

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