logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Integral Calculus
0 votes

Integrate :$\int \limits_6^8 \large\frac{[x^2]}{[x^2-28 x +196]+[x^2]}$$ dx$

\[\begin {array} {1 1} (a)\;1 \\ (b)\;\frac{3}{4} \\ (c)\;4 \\ (d)\;3 \end {array}\]
Can you answer this question?
 
 

1 Answer

0 votes
$\int \limits_a^b \large\frac{f(x)}{f(a+b-x)+f(x)} $$dx=\large\frac{b-a}{2}$
$\int \limits_6^8 \large\frac{[x^2]}{[(-x+14)^2]+[x^2]}$$ dx$
$a+b =14$
$\large\frac{a-b}{2}=\frac{8-6}{2}$
$\qquad=1$
Hence a is the correct answer
answered Dec 13, 2013 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...