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The initial rate for zero order reaction of the gaseous reaction $A(g)\rightarrow 4B(g)$ is $10^{-3}Msec^{-1}$. If the initial concentration of $A$ is $0.01\;M$ after $2\;sec$. Concentration of $B$ should be

$\begin{array}{1 1}(a)\;0.002M&(b)\;0.001M\\(c)\;0.008M&(d)\;0.004M\end{array}$

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$[A]_t=[A_o]-kt$
$\;\;\;\;\;\;=0.01-10^{-3}(2)$
$\;\;\;\;\;\;=0.008M$
$[B]_t=4(0.002)M$
$\;\;\;\;\;\;=0.008M$
Hence (c) is the correct answer.
answered Dec 13, 2013 by sreemathi.v
 

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