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The rate law for a reaction $A\rightarrow B$ is rate=$K[A]^m[B]^n$.On tripling the concentration of A and halving the concentration of B,the ratio of new rate to the earlier rate of the reaction will be as

$\begin{array}{1 1}(a)\;\large\frac{3^m}{2^n}&(b)\;\large\frac{2^n}{3^m}\\(c)\;\large\frac{3^n}{2^m}&(d)\;\large\frac{2^m}{3^n}\end{array}$

1 Answer

$\Rightarrow \large\frac{3^m}{2^n}$
answered Dec 16, 2013 by sreemathi.v
edited Jul 26, 2014 by balaji.thirumalai

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