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The ground state energy of hydrogen atom is -13.6eV. When its electron is in the first excited state, its excitation energy is :

$\begin {array} {1 1} (1)\;0 & \quad (2)\;3.4eV \\ (3)\;6.8eV & \quad (4)\;10.2eV \end {array}$

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n=1 me -13.6ev and n=2 me -3.4ev then excitation energy = final - initial energy then 10.2ev correct ans
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