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Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be :

$\begin {array} {1 1} (1)\;1:1 & \quad (2)\;1:3 \\ (3)\;3:1 & \quad (4)\;(3)^{\large\frac{1}{3}}:1 \end {array}$

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A)
nuclear densities are independent on mass number
Density = mass/volume Therefore d1 = m1/v d2 = m2/v The two nuclear volumes are same d1/d2=m1/v/m2/v =m1/m2 The two nuclear masses are in the ratio of 1/3
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