Ask Questions, Get Answers

Want to ask us a question? Click here
Home  >>  JEEMAIN and AIPMT  >>  Chemistry
0 votes

Bond dissociation enthalpy of $H_2,CI_2\: and \: HCI$ are 434, 242 and 431 $kJmol^{-1}$ respectively. Enthalpy of formation of HCI is :

$\begin {array} {1 1} (1)\;245\:kJmol^{-1} & \quad (2)\;93\: kJmol^{-1} \\ (3)\;-245\: kJmol^{-1} & \quad (4)\;-93\: kJmol^{-1} \end {array}$

Can you answer this question?

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App