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Home  >>  JEEMAIN and AIPMT  >>  Chemistry
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Bond dissociation enthalpy of $H_2,CI_2\: and \: HCI$ are 434, 242 and 431 $kJmol^{-1}$ respectively. Enthalpy of formation of HCI is :

$\begin {array} {1 1} (1)\;245\:kJmol^{-1} & \quad (2)\;93\: kJmol^{-1} \\ (3)\;-245\: kJmol^{-1} & \quad (4)\;-93\: kJmol^{-1} \end {array}$

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