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Consider the following reaction :$NaOH(aq)+HCl(aq)\rightarrow H_2O(l)+NaCl(aq)$.The rate of reaction can be found by observing change in concentration

$\begin{array}{1 1}(a)\;H_2O&(b)\;Cl^-\\(c)\;H^+&(d)\;Na^+\end{array}$

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$Cl^-$ & $NO^+$ ions are both sides.So we can't determine rate by observing them.
$H_2O$ is pure liquid,so its concentration can be kept nearly constant.
So monitoring change is concentration of $H^+$ we can determine rate.
Hence (c) is the correct answer.
answered Dec 17, 2013 by sreemathi.v
 

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