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An activated complex has

$\begin{array}{1 1}(a)\;\text{low potential energy and is stable}\\(b)\;\text{high potential energy and is stable}\\(c)\;\text{low potential energy and is unstable}\\(d)\;\text{high potential energy and is unstable}\end{array}$

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Activated complex has high potential energy and is unstable that's why it subsequently changes to products.
Hence (d) is the correct answer.
answered Dec 17, 2013 by sreemathi.v
 

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