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In the hydrocarbon

$CH_3 - CH_5 = CH - CH_2 - C \equiv CH$

6             5             4          3        2          1

The state of hybridization of carbons 1,3 and 5 are in the following sequence

$\begin {array} {1 1} (1)\;sP^3,sP^2,sP & \quad (2)\;sP^2,sP,sP^3 \\ (3)\;sP,sP^3,sP_2 & \quad (4)\;sP,sP^2,sP^3 \end {array}$

 

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