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Consider the following reaction: $\large\frac{1}{2}$$H_2(g)+\large\frac{1}{2}$$Cl_2(g)\rightarrow HCl(g)$ $\Delta H=20KJ$.The activation energy for formation of HCl is 150KJ.Then activation energy for decomposition of HCl will be

$\begin{array}{1 1}(a)\;150KJ\\(b)\;130KJ\\(c)\;20KJ\\(d)140KJ\end{array}$

1 Answer

The activation energy for decomposition will be $E_a=150-20=130KJ$
Hence (b) is the correct answer.
answered Dec 18, 2013 by sreemathi.v
 

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