logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Integral Calculus

Integrate : $\int (1+2x) (3+4x) .dx$

\[\begin {array} {1 1} (a)\;16 x +10+c \\ (b)\;\frac{8x^3}{3}+5x^2+3x+c \\ (c)\;8x^3+10x^2+3x+c \\ (d)\;None \end {array}\]

1 Answer

$\int (1+2x)(3+4x)dx$
=> $\int (3+10x +8x^2)dx$
=> $\int (8x^2 +10 x +3) dx$
=> $\large\frac{8x^3}{3} $$+5x^2+3x+c$
Hence b is the correct answer.
answered Dec 18, 2013 by meena.p
 
...