Browse Questions

# Integrate : $\int\large\frac{\cos 2x}{\cos ^ 2 x} $$dx $\begin {array} {1 1} (a)\;2x+\tan x +c \\ (b)\;-2x -\tan x+c \\ (c)\;-2x + \tan x +c \\ (d)\;2x - \tan x+c \end {array}$ Can you answer this question? ## 1 Answer 0 votes \int \large\frac{2 \cos ^2 -1}{\cos ^2 x}$$dx$
=> $\int (2- \sec^2 x) dx$
=> $2x - \tan x + c$
Hence d is the correct answer.