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# Integrate : $\int \large\frac{\cos 2x}{\cos ^2 x \sin ^2 x }$$dx $\begin {array} {1 1} (a)\;\cot x - \tan x +c \\ (b)\;\tan x - \cot x +c \\ (c)\;-\cot x -\tan x +c \\ (d)\;None \end {array}$ Can you answer this question? ## 1 Answer 0 votes \int \large\frac{\cos ^2 x- \sin ^2 x}{\cos ^2 x -\sin ^2 x}$$dx$
=> $\int cosec^2 x -\sec^2 x \;dx$
=> $-\cot x -\tan x +c$
Hence c is the correct answer.