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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Integral Calculus

Integrate : $\int \large\frac{\cos 2x}{\cos ^2 x \sin ^2 x }$$dx$

\[\begin {array} {1 1} (a)\;\cot x - \tan x +c \\ (b)\;\tan x - \cot x +c \\ (c)\;-\cot x -\tan x +c \\ (d)\;None \end {array}\]
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1 Answer

$\int \large\frac{\cos ^2 x- \sin ^2 x}{\cos ^2 x -\sin ^2 x}$$dx$
=> $\int cosec^2 x -\sec^2 x \;dx$
=> $ -\cot x -\tan x +c$
Hence c is the correct answer.
answered Dec 19, 2013 by meena.p
 
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