$\begin{array}{1 1}(a)\;47min\\(b)\;42.69min\\(c)\;45min\\(d)\;46.17min\end{array}$

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The rate law

$\large\frac{-d[A]}{dt}$$=k_1[A]$

$k_1=\large\frac{1}{[A]}\times \frac{d[A]}{dt}$

For a finite,small change

$k_1=-\large\frac{1}{[A]}\times \frac{\Delta [A]}{\Delta t}$

Since in beginning [A] is not changing appreciably ,we have

$\large\frac{\Delta A}{A}=$$1.5%$(per minute)

$k_1=\large\frac{0.015}{606}$$=2.5\times 10^{-4}s^{-1}$

$t_{1/2}=\large\frac{0.693}{k_1}=\frac{0.693}{2.5\times 10^{-4}s^{-1}}$

$\;\;\;\;\;=2.77\times 10^3s$

$\;\;\;\;\;=46.17min$

Hence (d) is the correct answer.

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