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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Integral Calculus

Integrate: $ \int \sqrt {x^2+4x+4}.dx$

\[\begin {array} {1 1} (a)\;x^2+2x+c\\ (b)\;\frac{x^2}{2}+2x+c \\ (c)\;x^2-2x+c \\ (d)\;None \end {array}\]

1 Answer

$=\int \sqrt {(x+2)}^2$$.dx$
=>$\int (x+2) dx$
=>$\large\frac{x^2}{2}$$+2x+c$
Hence b is the correct answer.
answered Dec 19, 2013 by meena.p
 
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