Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Integral Calculus
0 votes

Integrate : $\int \large\frac{1}{(4 \cos ^3 x -3 \cos x)^2}$$dx$

\[\begin {array} {1 1} (a)\;\tan 3x+c \\ (b)\;\frac{1}{3} \tan 3x+c \\ (c)\;\frac{1}{3}\tan^2 3x+c \\ (d)\;None \end {array}\]
Can you answer this question?

1 Answer

0 votes
$ \cos 3x = 4 \cos 3x - 3 \cos x$
=> $\int \sec^2 3x .dx$
=> $\tan (3x) \times \large\frac{1}{3} $$+c$
$\large\frac{1}{3}$$ \tan 3x+c$
Hence b is the correct answer.
answered Dec 19, 2013 by meena.p
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App