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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Integral Calculus
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Integrate : $\int \large\frac{1}{(4 \cos ^3 x -3 \cos x)^2}$$dx$

\[\begin {array} {1 1} (a)\;\tan 3x+c \\ (b)\;\frac{1}{3} \tan 3x+c \\ (c)\;\frac{1}{3}\tan^2 3x+c \\ (d)\;None \end {array}\]
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$ \cos 3x = 4 \cos 3x - 3 \cos x$
=> $\int \sec^2 3x .dx$
=> $\tan (3x) \times \large\frac{1}{3} $$+c$
$\large\frac{1}{3}$$ \tan 3x+c$
Hence b is the correct answer.
answered Dec 19, 2013 by meena.p
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