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If the space between two plates of a capacitor is filled with liquid of dielectric constant K, the capacitance of the capacitor:

(A) Increases by a factor of $ K$

(B) Decreases by a factor of $K$

(C) Increases by a factor of $K^2$

(D) Decreases by a factor of $K^2$

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1 Answer

Initial capacitance $=c=\large\frac{\in_0 A}{d}$
Final capacitamce $=c'=\large\frac{K \in _0 A}{d}$
So the capacitance of the capacitor is increase by factor of K.
Hence A is the correct answer.
answered Jan 3, 2014 by meena.p
 

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