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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Integral Calculus
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Integrate : $\int \large\frac{1}{\sin ^2 x \cos ^2 x} $$dx$

\[\begin {array} {1 1} (a)\;\sin x - \cos x +c \\ (b)\;\cos x- \sec x +c\\ (c)\;\tan x - \cot x +c \\ (d)\;None \end {array}\]
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1 Answer

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=> $\int \large\frac{\sin ^2 x +\cos ^2 x }{\sin ^2 x \cos ^2 x }$$dx$
=> $\int \large\frac{1}{\cos ^2 x} $$dx+\int \large\frac{1}{\sin ^2 x }$$dx$
=> $\int \sec^2 x dx+\int cosec ^2 x dx$
$ \tan x - \cot x +c$
Hence c is the correct answer.


answered Dec 21, 2013 by meena.p
edited Dec 22, 2013 by rvidyagovindarajan_1
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