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3-D Geometry
The distance of the plane $2x-3y+6z+14=0$ from origin is ?
$\begin{array}{1 1} 2 \\ 3 \\ 11 \\ 14 \end{array} $
jeemain
math
class12
ch11
3d-geometry
equation-of-a-plane
easy
q4
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asked
Dec 22, 2013
by
rvidyagovindarajan_1
edited
Apr 12, 2016
by
meena.p
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1 Answer
Toolbox:
The distance of the plane $ax+by+cz+d=0$ from origin = $\bigg|\large\frac{d}{\sqrt {a^2+b^2+c^2}}\bigg|$
The distance of the plane $2x-3y+6z+14=0$ from origin is $\large \frac{14}{\sqrt {4+9+36}}$
$=\large\frac{14}{7}$$=2$
answered
Dec 22, 2013
by
rvidyagovindarajan_1
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