logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Let $f : R\rightarrow [0,\infty]$ be such that $\lim\limits_{x\to 5}f(x)$ exists and $\lim\limits_{x\to 5}\large\frac{(f(x))^2-9}{\sqrt{|x-5|}}$ = 0. Then $\lim\limits_{x\to 5}f(x)$ equals

$(a)\;0\qquad(b)\;1\qquad(c)\;2\qquad(d)\;3$

Can you answer this question?
 
 

1 Answer

0 votes
$\lim\limits_{x\to 5}\large\frac{(f(x))^2-9}{\sqrt{|x-5|}}$$=0$
$\lim\limits_{x\to 5}[(f(x))^2-9$$]=0$
$\Rightarrow \lim\limits_{x\to 5}(f)=3$
Hence (d) is the correct answer.
answered Dec 23, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...