# The momentum of a photon of energy $1MeV$ in kgm/s, will be
$\begin {array} {1 1} (a)\;0.33 \times 10^6 & \quad (b)\;7\: v\: 10^{-24} \\ (c)\;10^{-22} & \quad (d)\;5 \times 10^{-22} \end {array}$