Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Integral Calculus
Answer
Comment
Share
Q)

Integrate : $ \int \sqrt {1+ \sin 4x}$$dx$

$(a)\;\frac{\cos 2x}{2} -\frac{\sin 2x}{2}+c \qquad(b)\;\frac{-\cos x}{2}+\frac{\sin x}{2}+c \qquad(c)\;\frac{\cos x}{2}-\frac{\sin x}{2}+c \qquad (d)\;\frac{-\cos 2x}{2}+\frac{\sin 2x}{2}+c $

1 Answer

Comment
A)
$\int \sqrt { \sin ^2 2x +\cos ^2 2x + 2 \sin 2x \cos 2 x }dx$
$\sin ^2 \alpha + \cos ^2 \alpha=1$
$\sin 2 \alpha = 2 \sin \alpha \cos \alpha$
$\int \sqrt { (\sin 2x+ \cos 2x)^2}$$dx$
$\int (\sin 2x+ \cos 2x) dx$
$ \large\frac{-\cos 2x}{2}+\frac{\sin 2x}{2}$$+c $
Hence d is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...