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If $\lim\limits_{x\to 0}\large\frac{\sin px}{\tan 3x}$$=4$ then value of p is

$(a)\;6\qquad(b)\;9\qquad(c)\;12\qquad(d)\;4$

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$\lim\limits_{x\to 0}\large\frac{\sin px}{\tan 3x}$
$\Rightarrow \lim\limits_{x\to 0}\large\frac{\sin px}{px}\times \frac{3x}{\tan 3x}\times \frac{p}{3}$
$\Rightarrow 1\times 1 \times \large\frac{p}{3}$
$\Rightarrow \large\frac{p}{3}$$=4$
$\Rightarrow p=12$
Hence (c) is the correct answer.
answered Dec 24, 2013 by sreemathi.v
 

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