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The maximum energy of the electrons released in photocell is independent of

$\begin {array} {1 1} (a)\;frequency\: of\: incident \: light & \quad (b)\; intensity\: of\: incident\: light \\ (c)\;nature\: of\: cathode\: surface & \quad (d)\;none\: of \: these \end {array}$


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And : (b) intensity of incident light
$E_{max} = hv - hv_{\circ}$


answered Dec 24, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1

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