Ans : (a)
For the $KE,\: K$ of an electron with velocity v, we have
$K=\large\frac{1}{2}\: m_ev^2$………..(i)
For de Broglie wavelength,
$ \lambda=h/m_ev$
$\Rightarrow \large\frac{v^2 = h^2 }{ \lambda^2m_e^2}$……….(ii)
Substituting eq. (ii) in (i),
$ K = \large\frac{m_eh^2}{2 \lambda^2m_e} \large\frac{h^2}{2\lambda^2m_e}$...........(iii)
$=\large\frac{ (6.6 \times 10^{-34} )^2 }{[2 \times (589 \times 10^{-9} )^2 \times 9.1 \times 10^{-31} ]}$
$≈ 69 \times 10^{-26}\: J$