logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  3-D Geometry
0 votes

The equation of the plane which is parallel to the plane $x-2y+2z-5=0$ and which is at a unit distance from origin is ?

$\begin{array}{1 1} (a)\;x-2y+2z-3=0\:\:\:\qquad\:\:(b)\:\:x-2y+2z+1=0\:\:\qquad\:\:(c)\:\:x-2y+2z-1=0\:\:\qquad\:\:(d)\:\:x-2y+2z+5=0 \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • Equation of any plane parallel to the plane $ax+by+cz+d=0$ is $ax+by+cz+d_1=0$
  • Distance of the plane $ax+by+cz+d=0\:\:$from origin is $ \bigg|\large\frac{d}{\sqrt {a^2+b^2+c^2}}\bigg|$
Let the eqn. of the plane parallel to $x-2y+2z-5=0$ be $x-2y+2z+d=0$
Given that this plane is at unit distance from origin.
$\Rightarrow\:\bigg|\large\frac{d}{\sqrt {1+4+4}}\bigg|=1$
$\Rightarrow\:d=\pm3$
$\therefore $ Required eqn. of the plane is $x-2y+2z-3=0$
answered Dec 26, 2013 by rvidyagovindarajan_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...