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From this figure describing photoelectric effect, we may infer correctly that :

$\begin {array} {1 1} (A)\;\text{$Na$ and $Al$ both have same threshold frequency}\\ (B)\;\text{maximum $K.E$ for both the metals depend linearly on the frequency} \\ (C)\;\text{the stopping potentials are different for $Na$ and $Al$ for the same change in frequency} \\ (D)\;\text{$Al$ is a more photosensitive material than $Na$} \end {array}$

 

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Ans : (b)
Since, stopping potential, $V_{\circ},\: ; eV_{\circ} = K.E_{max}$
i.e.,$ V_{\circ}$ is directly proportional to $K.E_{max}$

 

answered Dec 27, 2013 by thanvigandhi_1
edited Mar 13, 2014 by thanvigandhi_1
 

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