$\begin{array}{1 1} \text{(a) each carries one quarter of its previous momentum.}\\ \text{(b) each carries one quarter of its previous energy.} \\ \text{
(c) are half the previous number.} \\ \text{(d) are one quarter of the previous number. }\end{array}$

Ans : (d)

On doubling the distance the intensity becomes one fourth i.e. only one fourth of

photons now strike the target in comparison to the previous number. Since

photoelectric effect is a one photon-one electron phenomena, so only one-fourth

photoelectrons are emitted out of the target hence reducing the current to

one fourth the previous value.

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